SOLUTION: Prove that 7^(n+2)-35(7^n-1)/44(7^n+2) is equal to 1/49

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Question 199294: Prove that 7^(n+2)-35(7^n-1)/44(7^n+2) is equal to 1/49
Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
[ 7^(n+2) -35*7^9n-1)] / [ 44(7^(n+2) ) ] = 1/49
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[ 1-35*7^-3] / 44 = 1/49
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[ 1 - 35 / (49*7) ] / 44 = 1/49
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[ 1-5/49] / 44 = 1/49
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[49/49 -5/49 ] / 44 = 1/49
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[ 44 / 49 ] / 44 = 1/49
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(44/49) * (1/44) = 1/49 = 1/49,,,,,,ok