SOLUTION: Q: The ratio of the length of a retangular field to its width is 4:3. The perimeter is 308 meters. What are its dimensions? P = 2l + 2w Please give steps required for solving.

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Q: The ratio of the length of a retangular field to its width is 4:3. The perimeter is 308 meters. What are its dimensions? P = 2l + 2w Please give steps required for solving.       Log On


   

Question 189141: Q: The ratio of the length of a retangular field to its width is 4:3. The perimeter is 308 meters. What are its dimensions? P = 2l + 2w
Please give steps required for solving.
Thanks,
Blake
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
L=4w/3
2L+2w=P
2(4w/3)+2w=308 substitute 4w/3 for L
8w/3 + 2w = 308
8w+6w=924 multiply each side by 3 to eliminate fraction.
14w=924
w=66
L=88
.
Ed