SOLUTION: two military squads are 26 miles apart. they plan to rendezvous at some intermediate point. if one squad hikes 2/3 mph faster than the other, and they meet in 3 hrs, what is the ra

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Question 181114: two military squads are 26 miles apart. they plan to rendezvous at some intermediate point. if one squad hikes 2/3 mph faster than the other, and they meet in 3 hrs, what is the rate of the faster squad?
Found 2 solutions by ankor@dixie-net.com, josmiceli:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
two military squads are 26 miles apart. they plan to rendezvous at some
intermediate point. if one squad hikes 2/3 mph faster than the other,
and they meet in 3 hrs, what is the rate of the faster squad?
:
Let s = the speed of the faster squad
then
(s-2%2F3) = speed of the slow-pokes
:
The total dist of both squads = 26 mi, they both travel for 3 hrs:
write a distance equation dist = time * speed
:
3s + 3(s-2%2F3) = 26
Multiply what's inside the brackets
3s + 3s - 2 = 26
6s = 26 + 2
6s = 28
s = 28%2F6
s = 14/3 or 42%2F3 mph is the speed of the faster squad
:
:
check solution by finding the dist traveled by each (slower squad = 4 mph)
3 * 4 = 12
3 * 14%2F3 = 14
------------
Total 26 mi

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let r = the rate of the slower squad
Let d = the distance the slower squad travels in 3 hrs
given:
The rate of the faster squad is
%28r+%2B+%282%2F3%29%29
The distance the faster squad travels in 3 hrs is
26+-+d
---------------------
For slower squad:
(1) d+=+3r
For faster squad:
26+-+d+=+%28r+%2B+%282%2F3%29%29%2A3
26+-+d+=+3r+%2B+2
(2) d+=+24+-+3r
Subtract (1) from (2)
(2) d+=+24+-+3r
(1) -d+=+-3r
0+=+24+-+6r
6r+=+24
r+=+4 mi/hr
The rate of the faster squad is
r+%2B+%282%2F3%29+=+4.67mi/hr
The faster squad's rate was 4.67 mi/hr
check answer
d+=+3r
d+=+12 mi
26+-+d+=+%28r+%2B+%282%2F3%29%29%2A3
26+-+12+=+%28r+%2B+%282%2F3%29%29%2A3
14++=+3r+%2B+2
3r+=+12
r+=+4 mi/hr
OK