SOLUTION:

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION:       Log On


   



Question 177209:




Found 2 solutions by nerdybill, madhan_math:
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
8) Factor x^2 + 6a - 40
(x+10)(x-4)
.
9) Factor 3x^2 + 2x – 5
(3x+5)(x-1)

Answer by madhan_math(34) About Me  (Show Source):
You can put this solution on YOUR website!
8) Factor x^2 + 6x - 40
Ans:
Given equation is x^2+6x-40.
(To find the factor for this type of equation first we see that there is any coefficient in the high factor)
Here no coefficient with high power.
So first we consider the constant i.e.,-40.
Next we split this constant into mutliple of two variables also we note that the addition of two variables gives the coefficient of second higher power.
Therefore, -40 = 10 x -4 (10-4=+6)

Now the given equation can be written as
x^2+10x-4x-40 = 0
x(x+10)-4(x+10)=0
(x+10)(x-4)=0
x=-10 and x=4

Thus the factor x=-10,4.




9) Factor 3x^2 + 2x – 5
Ans:
Given equation is 3x^2+2x-5=0.
Here there is coefficient with high power (x^2).
So that coefficient is mutliply with the constant.
i.e., 3x(-5)= -15
-15 = 5 x-3 = 2(second high power coefficient)
Now the given equation can be written as
3x^2-3x+5x-5=0
3x(x-1) +5(x-1)=0
(3x+5)(x-1)=0
3x+5=0 and x-1=0
3x=-5 and x=1
x=-5/3 and x=1
Thus the factor of the given equation is
x = -5/3, 1