SOLUTION: I really messed up posting this the last time so I will try again please bare with me 4/(root(3,5x^2)

Algebra ->  Square-cubic-other-roots -> SOLUTION: I really messed up posting this the last time so I will try again please bare with me 4/(root(3,5x^2)      Log On


   

Question 173280: I really messed up posting this the last time so I will try again please bare with me 4/(root(3,5x^2)
Found 2 solutions by jim_thompson5910, Mathtut:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
4%2F%28root%283%2C5x%5E2%29%29 Start with the given expression


Multiply the fraction by root%283%2C5x%5E2%29%2Froot%283%2C5x%5E2%29 twice (to get a total of 3 copies of root%283%2C5x%5E2%29 in the denominator)



Now notice how


So let's replace the denominator with 5x%5E2


%284%2Aroot%283%2C5x%5E2%29root%283%2C5x%5E2%29%29%2F%285x%5E2%29


Now multiply 4%2Aroot%283%2C5x%5E2%29root%283%2C5x%5E2%29 out to get



So replace the the numerator with

%284x%2Aroot%283%2C25x%29%29%2F%285x%5E2%29


%284%2Aroot%283%2C25x%29%29%2F%285x%29 Reduce %284x%29%2F%285x%5E2%29 to get 4%2F%285x%29



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Answer:


So 4%2F%28root%283%2C5x%5E2%29%29 simplifies to %284%2Aroot%283%2C25x%29%29%2F%285x%29


In other words, 4%2F%28root%283%2C5x%5E2%29%29=%284%2Aroot%283%2C25x%29%29%2F%285x%29 where x%3C%3E0

Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
4%2Froot%283%2Cx%5E2%29given
:
4sqrt%28x%29%2F%28x+%29cross%28root%283%2Cx%5E2%29%29cross%28%28sqrt%28x%29%29%29mult by sqrt%28x%29top and bottom
:
4sqrt%28x%29%2Fx
: