SOLUTION: We are doing Volume of Prisms and Cylinders. The tablet held by the Statue of LIberty is approximately a rectangular prism with volume 1,107,096 inches-cubed. Tablet is 13

Algebra ->  Bodies-in-space -> SOLUTION: We are doing Volume of Prisms and Cylinders. The tablet held by the Statue of LIberty is approximately a rectangular prism with volume 1,107,096 inches-cubed. Tablet is 13       Log On


   

Question 171104This question is from textbook Pre-Algebra
: We are doing Volume of Prisms and Cylinders.
The tablet held by the Statue of LIberty is approximately a rectangular prism with volume 1,107,096 inches-cubed.
Tablet is 13 ft 7 inches in width and 27ft and 7 inches in length.
Estimate the thickness fo the tablet. ---------------I know that V=Bh. But I'm really confused. Please help.

This question is from textbook Pre-Algebra

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Starting with:
V+=+Bh where B = area of the base and h = height (or thickness in this problem).
Find the area of the base (B = W*L). Convert dimensions to inches:
W = 13ft 7in = 13(12)+7 = 163 in.
L = 27ft 7in = 27(12)+7 = 331 in.
B+=+163%2A331
B+=+53593sq.in.
To find h, the thickness, solve the volume formula for h.
V+=+Bh Divide by B.
h+=+V%2FB V is given as 1,107,096 and B = 53593, so...
h+=+1107096%2F53593
h+=+20.657inches.
The thickness is 20.7 inches.