Question 168655: Find 4 consecutive even intergers such that the largest is 2 more than half the sum of the first 3 integers Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! lets call our consecutive even integers: x, x+2, x+4, x+6
(x+6)=1/2(x+(x+2)+(x+4))+2------multiply all terms by 2
2x+12=x+x+2+x+4+4
:
2x+12=3x+10
: so integers are 2,4,6,and 8