SOLUTION: ok i need to find out how much shorter a 1 meter rod will become if it is moving at 60 miles per hour the equation it give me to solve it is L to the root of 1-v squared divided by

Algebra ->  Square-cubic-other-roots -> SOLUTION: ok i need to find out how much shorter a 1 meter rod will become if it is moving at 60 miles per hour the equation it give me to solve it is L to the root of 1-v squared divided by      Log On


   

Question 167615: ok i need to find out how much shorter a 1 meter rod will become if it is moving at 60 miles per hour the equation it give me to solve it is L to the root of 1-v squared divided by c square
were L is the lengh
v is the velocity
and c is the speed of light about 186,000 miles per second
if anyone could help that be nice
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
ok i need to find out how much shorter a 1 meter rod will become if it is moving at 60 miles per hour the equation it give me to solve it is L to the root of 1-v squared divided by c square
were L is the lengh
v is the velocity
and c is the speed of light about 186,000 miles per second
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The Lorentz Factor is:
1%2F%28sqrt%281-%28v%5E2%2Fc%5E2%29%29%29
c is in miles per second, so convert 60 mph to miles per second:
v =60 mph = 1 mile per minute
= 1/60 mile per second
%28v%2Fc%29%5E2+=+1%2F%2860%2A186000%29%5E2
= ++8.02918777%2A10%5E%28-15%29
If you use a small calculator and subtract that from 1, you get just 1. It's too many digits for them.
Use the MS Windows calculator in the Scientific view.
A 1 meter rod is shortened by 4.01459385*10^(-15) meters
That's 0.00000000000000401459 meters.