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Question 16205: find 3 consecutive integers that are equal to 99
Answer by elima(1433)   (Show Source):
You can put this solution on YOUR website! find 3 consecutive integers that are equal to 99
Let x = the first integer;
So, x+1=second integer
x+2=third integer
So we have;
x+(x+1)+(x+2)=99
3x+3=99
3x=96
x=32
So our first integer is 32, can you figure out what the next two are?
Hope you get it
=)
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