SOLUTION: I am not sure if I know what I am doing, I am taking an online algebra class. I am required to solve the following linear equations and graph result. This is how thought it should

Algebra ->  Graphs -> SOLUTION: I am not sure if I know what I am doing, I am taking an online algebra class. I am required to solve the following linear equations and graph result. This is how thought it should      Log On


   

Question 156688: I am not sure if I know what I am doing, I am taking an online algebra class. I am required to solve the following linear equations and graph result.
This is how thought it should be solved:
y=5x-2, 2+y=5x-2+2, 2+y/5=5x/5, 2+y=x
My other problem is how do I graph answer?

I did not include textbook information; our work is given my online professor.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Are you trying to graph y=5x-2?? If you are, I'm not sure why you are solving for "x" (when graphing you ALWAYS solve for "y")




Looking at y=5x-2 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=5 and the y-intercept is b=-2


Since b=-2 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point




Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is 5, this means:

rise%2Frun=5%2F1


which shows us that the rise is 5 and the run is 1. This means that to go from point to point, we can go up 5 and over 1



So starting at , go up 5 units


and to the right 1 unit to get to the next point



Now draw a line through these points to graph y=5x-2

So this is the graph of y=5x-2 through the points and