SOLUTION: The ratio of the # of Conor's marbles to the # of Lillian's marbles is 3:4. After Conor bought another 60 marbles, he had twice as many marbles as Lillian. How many marbles did C

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: The ratio of the # of Conor's marbles to the # of Lillian's marbles is 3:4. After Conor bought another 60 marbles, he had twice as many marbles as Lillian. How many marbles did C      Log On


   



Question 156257: The ratio of the # of Conor's marbles to the # of Lillian's marbles is 3:4. After Conor bought another 60 marbles, he had twice as many marbles as Lillian. How many marbles did Conor have at first?
I don't know how to start to figure this out. Do I use x represent Conor's marbles or Lillian's marbles?

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The ratio of the # of Conor's marbles to the # of Lillian's marbles is 3:4. After Conor bought another 60 marbles, he had twice as many marbles as Lillian. How many marbles did Conor have at first?
:
Let x = no. marbles Conor had originally
Let y = no. marbles Lillian has
:
Write an equation for the statement:
"The ratio of the # of Conor's marbles to the # of Lillian's marbles is 3:4."
x%2Fy = 3%2F4
Cross multiply and we have:
4x = 3y
:
"After Conor bought another 60 marbles, he had twice as many marbles as Lillian."
x + 60 = 2y
x = (2y-60)
:
Substitute (2y-60) for x in the 1st equation
4(2y-60) = 3y
8y - 240 = 3y
8y - 3y = 240
5y = 240
y = 240%2F5
y = 48 marbles for Lillian
;
Find x
x = 2y - 60
x = 2(48) - 60
x = 96 - 60
x = 36 marbles for Conor originally
;
:
Check solution
36%2F48 = 3%2F4