SOLUTION: 1. The perimeter of a rectangular box is 42 inches. The length of the box is 15 inches more than the width. Determine the dimensions of the rectangle in terms of feet

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Question 140017: 1. The perimeter of a rectangular box is 42 inches. The length of the box is 15 inches
more than the width. Determine the dimensions of the rectangle in terms of feet
Also find the area of the box in terms of feet. Draw the diagram by showing the
dimensions.
(a) How will you set up the problem.
(b) What are the two linear equations.
(c) What is the product of two dimensions of the rectangle.
(d) How is this product different from perimeter. Interpret on that.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
a)

Let L=length, W=width


b)
Since "The length of the box is 15 inches more than the width", this means the first equation is L=W%2B15


Remember the perimeter formula is P=2%2AW%2B2%2AL

If we plug in P=42, we get the second equation:

42=2%2AW%2B2%2AL


So the two equations are:
L=W%2B15
42=2%2AW%2B2%2AL


c) the product of the two dimensions of the rectangle is

W%2AL=W%2A%28W%2B15%29=W%5E2%2B15W


d) The perimeter is a linear equation while the product is a nonlinear equation