SOLUTION: given p(x) = -x^2-x^3+10x, find p(-1)

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Question 131046: given p(x) = -x^2-x^3+10x, find p(-1)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!




p%28x%29=-1x%5E2-1x%5E3%2B10x Start with the given function


p%28-1%29=-1%28-1%29%5E2-1%28-1%29%5E3%2B10%28-1%29 Plug in x=-1


p%28-1%29=-1%2A1-1%2A-1%5E3%2B10%2A-1 Raise -1 to the 2nd power to get 1


p%28-1%29=-1-1%2A-1%5E3%2B10%2A-1 Multiply -1 and 1 to get -1


p%28-1%29=-1-1%2A-1%2B10%2A-1 Raise -1 to the 3rd power to get -1


p%28-1%29=-1--1%2B10%2A-1 Multiply 1 and -1 to get -1


p%28-1%29=0%2B10%2A-1 Subtract -1 from -1 to get 0


p%28-1%29=0%2B-10 Multiply 10 and -1 to get -10


p%28-1%29=-10 Add 0 and -10 to get -10