SOLUTION: I can not figure this out. Please help me, I just can not get word problems correct. Thanks so much for your help. I need this help by tomorrow please.
In 1991, the life expectanc
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In 1991, the life expectanc
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Question 129431: I can not figure this out. Please help me, I just can not get word problems correct. Thanks so much for your help. I need this help by tomorrow please.
In 1991, the life expectancy of males in a certain country 68.9 years. In 1997 it was 71.7 years. Let E represent the life expectancy in year t and let t represent the number of years since 1991.
The linear function that fits the data is. E(t)= _t + _ ? Round answer to the nearest tenth.
Also, Use the function to predict the life expectancy of males in 2009.
You can put this solution on YOUR website! In 1991, the life expectancy of males in a certain country 68.9 years. In 1997 it was 71.7 years. Let E represent the life expectancy in year t and let t represent the number of years since 1991.
The linear function that fits the data is. E(t)= _t + _ ? Round answer to the nearest tenth.
Also, Use the function to predict the life expectancy of males in 2009.
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I'm sure you know how to find the equation of a line if you have two points.
Well, in this problem you are given two points: (0,68.9) and (6,71.7)
slope = (71.7-68.9) / (6-0) = 0.466667
Form is E(t) = slope(years since 1991) + b
Solve for "b"
68.9 = 0.466667*0 + b
b= 68.9
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EQUATION:
E(t) = 0.466667t + 68.9
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Use the function to predict the life expectancy of males in 2009.
E(2009-1991) = 0.46666667*18 + 68.9
E(18) = 77.3 yrs.
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Cheers,
Stan H.
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