SOLUTION: the question says "state the slope of a line parallel to the line passing through (-1,-1) and (3,2) then state the slope of a line perpendicular to it. now what i did is plot (-1,-

Algebra ->  Linear-equations -> SOLUTION: the question says "state the slope of a line parallel to the line passing through (-1,-1) and (3,2) then state the slope of a line perpendicular to it. now what i did is plot (-1,-      Log On


   

Question 11799: the question says "state the slope of a line parallel to the line passing through (-1,-1) and (3,2) then state the slope of a line perpendicular to it. now what i did is plot (-1,-1) and (3,2) but i dont know what to do from there. im stuck. i do know the formula to the slope but i dont know if i should use that because it wont tell me the slope of the line parallel or perpendicular to it. or will it? thank you so much for all your help
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
You can do this problem with algebra. The key is remembering that parallel lines have identical slopes and perpendicular lines have slopes that are the negative reciprocal of each other.
First, find the slope of the line passing through the given points (-1, -1) and (3, 2). You know the formula.
m+=+%28y2-y1%29%2F%28x2-x1%29
m+=+%282-%28-1%29%29%2F%283-%28-1%29%29
m+=+3%2F4
The slope of the line passing through the given points is m = 3/4
The slope of a parallel line is also m = 3/4
The slope of a perpendicular line is -4/3