SOLUTION: y2+11y=28

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Question 117145:
y2+11y=28
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
Y^2+11Y=28
Y^2+11Y-28=0
USING THE QUADRATIC EQUATION:x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
WE GET
Y=(-11+-SQRT[11^2-4*1*-28])/2*1
Y=(-11+-SQRT[121+112])/2
Y=(-11+-SQRT[233)/2
Y=(-11+-15.26)/2
Y=(-11+15.26)/2
Y=4.26/2
Y=2.13 ANSWER.
Y=(-11-15.26)/2
Y=-26.26/2
Y=-13.13 ANSWER.