SOLUTION: One number is 4 less than another. If 10 times the smaller number minus 3 times the larger number is 51, find the two numbers.
So is this x(x-4)=51 I am lost
Thanks
Question 106672: One number is 4 less than another. If 10 times the smaller number minus 3 times the larger number is 51, find the two numbers.
So is this x(x-4)=51 I am lost
Thanks Answer by rcmcc(152) (Show Source):
You can put this solution on YOUR website! Word problems are tricky to understand. The easiest way to derive an equation is to go step by step.
the first equation you can find is simple.
y=x-4
where x is the larger number and y is the smaller one
so if y is the smaller number 10x y subtracting 3x the larger number x looks like this
10y-3x=51
so your two equations are below
y=x-4
10y-3x=51
because you have y isolated you can substitute it in for the second equation
10y-3x=51
10(x-4)-3x=51
expand the brackets
10x-40-3x=51
simplify
7x-40=51
bring the 40 to the other side
7x=91
divide by 7
x=13
because you have the larger number subtract 4 to find the smaller number
your two numbers are (13 and 9)
