document.write( "Question 136497: Fred jogs uphill at 8mph to work.On his way home (downhill) he averages 11mph and takes him 15 min less time.How far does he live from work? \n" ); document.write( "
Algebra.Com's Answer #99984 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 8t=11(t-.25) \n" ); document.write( "8t=11t-2.75 \n" ); document.write( "8t-11t=-2.75 \n" ); document.write( "-3t=-2.75 \n" ); document.write( "t=-2.75/-3 \n" ); document.write( "t=.917 hours is his time. \n" ); document.write( "8*.917=7.33 miles is the distance to his work. \n" ); document.write( "proof \n" ); document.write( "11(.917-.25)=11*.667=7.33 mles. \n" ); document.write( " |