document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=136456>Question 136456</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many odd numbers of four different digits can be formed by choosing from the digits 1, 2, 3, 4, and 5? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99946 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99946\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In order for the number to be odd, the 'ones digit' must be odd. The other digits can be anything.\r<BR>\n" );
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document.write( "The number will be of the form ABCD - where D must be odd.\r<BR>\n" );
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document.write( "How many choices do we have for the digit 'A'? We can use any of the 5 given digits.<BR>\n" );
document.write( "How many for B? Again 5 digits<BR>\n" );
document.write( "How many for C? Again 5 digits?<BR>\n" );
document.write( "How many for D? Only 3 (1,3 and 5).\r<BR>\n" );
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document.write( "Do the number of combinations will be<BR>\n" );
document.write( "5*5*5*3  = 375 </SPAN>\n" );
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