document.write( "Question 136433: find two imaginary numbers in the form a + bi whose product = 17. Neither a nor b may equal zero.\r
\n" ); document.write( "\n" ); document.write( "Has me stumped. Any help is appreciated.
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Algebra.Com's Answer #99926 by josmiceli(19441)\"\" \"About 
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In order to get rid of any \"i\" in the result, the factors
\n" ); document.write( "would have to be of the form \"a+%2B+bi\" and \"a+-+bi\", then
\n" ); document.write( "\"%28a+%2B+bi%29%28a+-+bi%29+=+a%5E2+-+b%5E2%2A%28-1%29\"
\n" ); document.write( "\"a%5E2+-+b%5E2%2A%28-1%29+=+a%5E2+%2B+b%5E2\", and it's given that
\n" ); document.write( "\"a%5E2+%2B+b%5E2+=+17\"
\n" ); document.write( "I know that \"16\" and \"1\" are both squares and add up to \"17\", so
\n" ); document.write( "\"4%5E2+%2B+1%5E2+=+17\"
\n" ); document.write( "\"a+=+4\"
\n" ); document.write( "\"b+=+1\"
\n" ); document.write( "So, the numbers are
\n" ); document.write( "\"4+%2B+i\" and
\n" ); document.write( "\"4+-+i\"
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