document.write( "Question 136422: divide:\r
\n" ); document.write( "\n" ); document.write( "4-2i over 3+5i
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Algebra.Com's Answer #99921 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
divide:
\n" ); document.write( "4-2i over 3+5i
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\n" ); document.write( "Multiply numerator and denominator by 3-5i to get:
\n" ); document.write( "= [(4-2i)(3-5i)]/[9+25]\r
\n" ); document.write( "\n" ); document.write( "= [12-10 -20i-6i]/34\r
\n" ); document.write( "\n" ); document.write( "= [2 - 26i]/24\r
\n" ); document.write( "\n" ); document.write( "= (1/12) - (13/12)i\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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