document.write( "Question 136374: Please help! I'm totally stuck...
\n" ); document.write( "Jennifer is four years older than her sister, Sue. In four years she will be twice as old as Sue was 5 years ago. Find their ages now.
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Algebra.Com's Answer #99890 by checkley77(12844)\"\" \"About 
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let Jennifer's age=x+4
\n" ); document.write( "her sister's age=x
\n" ); document.write( "(x+4)+4=2(x-5)
\n" ); document.write( "x+8=2x-10
\n" ); document.write( "x-2x=-10-8
\n" ); document.write( "-x=-18
\n" ); document.write( "x=18 which is the sister's age now.
\n" ); document.write( "18+4=22 Jennifer's age now.
\n" ); document.write( "proof
\n" ); document.write( "22+4=2(18-5)
\n" ); document.write( "26=2*13
\n" ); document.write( "26=26
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