document.write( "Question 136374: Please help! I'm totally stuck...
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document.write( "Jennifer is four years older than her sister, Sue. In four years she will be twice as old as Sue was 5 years ago. Find their ages now.
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Algebra.Com's Answer #99890 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! let Jennifer's age=x+4 \n" ); document.write( "her sister's age=x \n" ); document.write( "(x+4)+4=2(x-5) \n" ); document.write( "x+8=2x-10 \n" ); document.write( "x-2x=-10-8 \n" ); document.write( "-x=-18 \n" ); document.write( "x=18 which is the sister's age now. \n" ); document.write( "18+4=22 Jennifer's age now. \n" ); document.write( "proof \n" ); document.write( "22+4=2(18-5) \n" ); document.write( "26=2*13 \n" ); document.write( "26=26 \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |