document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=136366>Question 136366</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Do you know compounding interest; Pe rt;  find the \"r\" rate of interest<BR>\n" );
document.write( "At what interest rate must 4800 be compounded annually to equal 9051.12 after 13 years, trying to find a formula like this in one of my 6 books, and I could find P, T, A but not \"r\", <BR>\n" );
document.write( "raysecrets @hotmail.com, I have been working on this homework problem for 2 days now.  Any help will be great.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99888 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99888\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FV=P(1+r)^n<BR>\n" );
document.write( "__ FV is the future value<BR>\n" );
document.write( "__ P is the starting amount (principal)<BR>\n" );
document.write( "__ r is the interest rate per compounding period (as a decimal)<BR>\n" );
document.write( "__ n is the number of compounding periods\r<BR>\n" );
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document.write( "the \"Pe rt\" is for continuous compounding __ e is the base for natural logs ( Euler's number)\r<BR>\n" );
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document.write( "9051.12=4800(1+r)^13 __ dividing by 4800 __ 9051.12/4800=(1+r)^13\r<BR>\n" );
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document.write( "taking the log __ log(9051.12/4800)=13(log(1+r))\r<BR>\n" );
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document.write( "dividing by 13 __ (log(9051.12/4800))/13=log(1+r)\r<BR>\n" );
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document.write( "taking antilog __ 10^((log(9051.12/4800))/13)=1+r\r<BR>\n" );
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document.write( "subtracting 1 __ (10^((log(9051.12/4800))/13))-1=r\r<BR>\n" );
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