document.write( "Question 136313: sqrt T + 12 - T = 0\r
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document.write( "T+12-T=0
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document.write( "sqrt(T+12)-T=0
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document.write( "sqrt(T+12)=X
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document.write( "(sqrtT+12)^2=T^2
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document.write( "T+12=T^2
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document.write( "T^2-T-12=0\r
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document.write( "I came up with (T = 4)(T-3) and I don't if I'm right please help! \n" );
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Algebra.Com's Answer #99885 by oscargut(2103)![]() ![]() You can put this solution on YOUR website! if equation is: \n" ); document.write( "sqrt (T + 12) - T = 0 (eq 1) \n" ); document.write( "then you did it well and \n" ); document.write( "T^2-T-12=0 (eq 2) \n" ); document.write( "T=4 and T=-3\r \n" ); document.write( "\n" ); document.write( "but solutions of the (eq 1) are included in solutions of (eq 2) \n" ); document.write( "(-3 is a solution of the eq 2 but not a solution of eq 1)\r \n" ); document.write( "\n" ); document.write( "Answer: T=4 \n" ); document.write( " |