document.write( "Question 136313: sqrt T + 12 - T = 0\r
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\n" ); document.write( "\n" ); document.write( "T+12-T=0
\n" ); document.write( "sqrt(T+12)-T=0
\n" ); document.write( "sqrt(T+12)=X
\n" ); document.write( "(sqrtT+12)^2=T^2
\n" ); document.write( "T+12=T^2
\n" ); document.write( "T^2-T-12=0\r
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\n" ); document.write( "\n" ); document.write( "I came up with (T = 4)(T-3) and I don't if I'm right please help!
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Algebra.Com's Answer #99885 by oscargut(2103)\"\" \"About 
You can put this solution on YOUR website!
if equation is:
\n" ); document.write( "sqrt (T + 12) - T = 0 (eq 1)
\n" ); document.write( "then you did it well and
\n" ); document.write( "T^2-T-12=0 (eq 2)
\n" ); document.write( "T=4 and T=-3\r
\n" ); document.write( "\n" ); document.write( "but solutions of the (eq 1) are included in solutions of (eq 2)
\n" ); document.write( "(-3 is a solution of the eq 2 but not a solution of eq 1)\r
\n" ); document.write( "\n" ); document.write( "Answer: T=4
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