document.write( "Question 136353: Please help, it says to solve by completing the square.
\n" ); document.write( "x^2-3x+1=0
\n" ); document.write( "What I got for this was x-2 x+8 2-83
\n" ); document.write( "I am not so sure about my answer, please help! Thank You=)
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Algebra.Com's Answer #99878 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
Given: \"x%5E2-3x%2B1=0\"\r
\n" ); document.write( "\n" ); document.write( "to complete the square, use this format
\n" ); document.write( "(ax^2 + 2abx + b^2)
\n" ); document.write( "We are given
\n" ); document.write( "\"x%5E2-3x%2B1=0\" , so a = 1 and 2ab=-3 --> b = -3/2 --> b^2 = 9/4\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-3x+%2B+9%2F4++%2B1=+%289%2F4%29\" whatever you do to one side, you need to do to the other\r
\n" ); document.write( "\n" ); document.write( "\"%28x-+1.5%29%5E2+=+%289%2F4%29+-+1+\"
\n" ); document.write( "\"+%28x-1.5%29%5E2+=+5%2F4+\"
\n" ); document.write( "\"+%28x-1.5%29+=+sqrt%285%2F4%29\"
\n" ); document.write( "\"x+=+sqrt%285%2F4%29+%2B+1.5+\"
\n" ); document.write( "\"x+=+1.5+%2B+sqrt%285%29%2F2\"
\n" ); document.write( "\"x+=+1.5+-+sqrt%285%29%2F2\"
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