document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=136339>Question 136339</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the perimeter and the area of the playing area of each table.<BR>\n" );
document.write( "50in.by100in,44inby88in.,38in.by76in. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99855 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99855\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 50in.by100in.<BR>\n" );
document.write( "2*50+2*100=100+200=300in. perimeter.<BR>\n" );
document.write( "50*100=5,000 in^2 area.<BR>\n" );
document.write( "44inby88in.<BR>\n" );
document.write( "2*44+2*88=88+176=264in perimeter.<BR>\n" );
document.write( "44*88=3,872 in^2 area.<BR>\n" );
document.write( "38in.by76in<BR>\n" );
document.write( "2*38=2*76=76+152=228in perimeter.<BR>\n" );
document.write( "38*76=2,888in^2 area.  </SPAN>\n" );
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