document.write( "Question 136344: how do i graph x+2y=-6? \n" ); document.write( "
Algebra.Com's Answer #99852 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
You can start by getting your equation into the slope-intercept form: y = mx+b
\n" ); document.write( "\"x%2B2y+=+-6\" Subtract x from both sides.
\n" ); document.write( "\"2y+=+-x-6\" Divide both sides by 2.
\n" ); document.write( "\"y+=+%28-1%2F2%29x-3\"
\n" ); document.write( "Now you need only two points to draw the graph of a linear equation.
\n" ); document.write( "First. let x = 0 then solve for y.
\n" ); document.write( "\"y+=+%28-1%2F2%29%280%29-3\"
\n" ); document.write( "\"y+=+-3\"
\n" ); document.write( "First point is (0,-3)
\n" ); document.write( "Now let y = 0 and solve for x.
\n" ); document.write( "\"0+=+%28-1%2F2%29x-3\" Add 3 to both sides.
\n" ); document.write( "\"3+=+%28-1%2F2%29x\" Multiply both sides by -2.
\n" ); document.write( "\"-6+=+x\"
\n" ); document.write( "Second point is (-6, 0)
\n" ); document.write( "Now plot these two point on your graph paper and draw a straight line through them. You should get the graph shown here:
\n" ); document.write( "\"graph%28400%2C400%2C-8%2C5%2C-5%2C5%2C%28-1%2F2%29x-3%29\"
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