document.write( "Question 136287: Please help, solve by completing the square: 2x^2-3x+1=0
\n" ); document.write( "I tried solving it and got no real solution, but I am not sure,please help Thank You=)
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Algebra.Com's Answer #99838 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"2x%5E2+-+3x+%2B+1+=+0\"
\n" ); document.write( "divide both sides by \"2\"
\n" ); document.write( "\"x%5E2+-+%283%2F2%29x+%2B+%281%2F2%29+=+0\"
\n" ); document.write( "complete the square
\n" ); document.write( "\"x%5E2+-+%283%2F2%29x+%2B+%283%2F4%29%5E2+%2B+%288%2F16%29+=+%283%2F4%29%5E2\"
\n" ); document.write( "subtract \"8%2F16\" from both sides
\n" ); document.write( "\"x%5E2+-+%283%2F2%29x+%2B+%289%2F16%29+=+%289%2F16%29+-+%288%2F16%29\"
\n" ); document.write( "\"%28x+-+%283%2F4%29%29%5E2+=+1%2F16\"
\n" ); document.write( "take square root of both sides
\n" ); document.write( "\"x+-+%283%2F4%29+=+1%2F4\"
\n" ); document.write( "\"x+=+1\"
\n" ); document.write( "also
\n" ); document.write( "\"x+-+%283%2F4%29+=+-%281%2F4%29\"
\n" ); document.write( "\"x+=+1%2F2\"
\n" ); document.write( "Check answers by substituting back into equation
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