document.write( "Question 136254: Colin invested $32,000, part at 8% and part at 12%. If the total interest at the end of the year is $3,160, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #99828 by checkley77(12844)\"\" \"About 
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.12x+.08(32,000-x)=3,160
\n" ); document.write( ".12x+2,560-.08x=3,160
\n" ); document.write( ".04x=3,160-2,560
\n" ); document.write( ".04x=600
\n" ); document.write( "x=600/.04
\n" ); document.write( "x=15,000 invested @ 12%.
\n" ); document.write( "32,000-15,000=17,000 invested @ 8%.
\n" ); document.write( "proof
\n" ); document.write( ".12*15,000+.08*17,000=3,160
\n" ); document.write( "1,800+1,360=3,160
\n" ); document.write( "3,160=3,160
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