document.write( "Question 136254: Colin invested $32,000, part at 8% and part at 12%. If the total interest at the end of the year is $3,160, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #99828 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .12x+.08(32,000-x)=3,160 \n" ); document.write( ".12x+2,560-.08x=3,160 \n" ); document.write( ".04x=3,160-2,560 \n" ); document.write( ".04x=600 \n" ); document.write( "x=600/.04 \n" ); document.write( "x=15,000 invested @ 12%. \n" ); document.write( "32,000-15,000=17,000 invested @ 8%. \n" ); document.write( "proof \n" ); document.write( ".12*15,000+.08*17,000=3,160 \n" ); document.write( "1,800+1,360=3,160 \n" ); document.write( "3,160=3,160 \n" ); document.write( " \n" ); document.write( " |