document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=136252>Question 136252</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1931914141/algebrahomeworkh>Crossing the River with Dogs</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Eric a health care enthusiast enjoys mixing his own beverages. His current favortie is a carrot drink that conatins 40% pure carrot juice. He has been to the store and has found some concentrated juice that is 60% pure carrot juice. His weife, Alcia found some carrot juice on sale and she brought home 80 quarts. It contains 12% pure carrot juice. How many quarts of the cocentrated 60% carrot juice does Eric need to add to the 80 quarts that Alicia brought home to produce his perfect drink containg 40% carrot juice? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99815 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99815\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=number of quarts of the 60% juice needed\r<BR>\n" );
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document.write( "Now we know that the pure carrot juice in the 60% juice (0.60x) plus the amount of pure carrot juice in the 12% juice (0.12*80) has to equal the amount of pure carrot juice in the final mixture (0.40(80+x)) so our equation to solve is:\r<BR>\n" );
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document.write( "0.60x+0.12*80=0.40(80+x) get rid of parens\r<BR>\n" );
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document.write( "0.60x+9.6=32+0.40x subtract 0.40x and also 9.6 from each side\r<BR>\n" );
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document.write( "0.60x-0.40x+9.6-9.6=0.40x-0.40x+32-9.6  collect like terms\r<BR>\n" );
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document.write( "0.20x=22.4  divide both sides by 0.20\r<BR>\n" );
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document.write( "x= 112 --------------------number of qts of 60% juice needed\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "0.60*112+0.12*80=0.40*192<BR>\n" );
document.write( "67.2+9.6=76.8<BR>\n" );
document.write( "76.8=76.8\r<BR>\n" );
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document.write( "Hope this helps---ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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