document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=20718>Question 20718</A>: <I><SPAN STYLE=\"word-break: break-all;\"> CAN SOMEONE, ANYONE PLEASE PLEASE HELP ME!!! I really need help.  What is the value of X  in the equation, log<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2 ALIGN=MIDDLE  ALT=\"2\"   DISABLED_style= \"max-width:90%; height:auto;\" >(2x+8) - log<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2 ALIGN=MIDDLE  ALT=\"2\"   DISABLED_style= \"max-width:90%; height:auto;\" >(2x^2+21x+61) = -3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9980 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i think you mean logs are to base 2..taking that and using the formula,<BR>\n" );
document.write( "log x to base y = log x/log y<BR>\n" );
document.write( "so we get<BR>\n" );
document.write( "log(2x+8)/log 2+log (2x^2+21x+61)/log 2=-3<BR>\n" );
document.write( "multiplying through out with log 2<BR>\n" );
document.write( "log(2x+8)+log(2x^2+21x+61)=-3log 2=log 2^(-3)==log(1/2^3)=log(1/8)<BR>\n" );
document.write( "log(2x+8)(2x^2+21x+61)=log(1/8)<BR>\n" );
document.write( "(2x+8)(2x^2+21x+61)=(1/8)<BR>\n" );
document.write( "i hope now you can continue from here<BR>\n" );
document.write( "to simplify and factorise to get the answers </SPAN>\n" );
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