document.write( "Question 136225: I need to figure out how to set these up. Thank you
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document.write( "You can use 1 mile = 5,280 feet for your conversions
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document.write( "1.Many people know that the weight of an object varies on different planets, but did you know that the weight of an object on earth also varies according to the elevation of the object? In particular, the weight of an object follows this equation: w=Cr^-2 , where C is a constant, and r is the distance that the object is from the center of the earth. \r
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document.write( "a.Solve the equation w=Cr^-2 for r. \r
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document.write( "b.Suppose that an object is 100 pounds when it is at sea level. Find the value of C that makes the equation true. (Sea level is 3,963 miles from the center of the earth.) \r
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document.write( "c.Use the value of C you found in the previous question to determine how much the object would weigh in \r
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document.write( "i. Death Valley (282 feet below sea level) \r
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document.write( "ii. The top of Mt McKinley (20,430 feet above sea level) \r
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Algebra.Com's Answer #99788 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! a. Solve \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b. You first need to solve for C. Use what we discovered in part a. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c.i. The radius of the earth is given in miles, and you calculated C on that basis, so you need to convert the difference between Death Valley's elevation and sea level, 282 feet into miles, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c.ii. Same process, except that you need to calculate |