document.write( "Question 136241: A horse and a cow togather cost $800.the horse is sold a a profit of 10% and the cow t loss of 10%.If the total profit of 2.5% is made,what is the cost price of the horse?
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Algebra.Com's Answer #99786 by solver91311(24713)\"\" \"About 
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Cost of horse: \"h\"
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\n" ); document.write( "Total cost: \"h+%2B+c+=+800\", which can be written: \"h=800-c\"\r
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\n" ); document.write( "\n" ); document.write( "Sell price of horse: \"h+%2B+.1h\"
\n" ); document.write( "Sell price of cow: \"c+-+.1c\"
\n" ); document.write( "Total sell price: \"%28h%2B.1h%29%2B%28c-.1c%29\"\r
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\n" ); document.write( "\n" ); document.write( "Total profit of 2.5% means total sell price of \"800+%2B+.025%2A800=820\", so:
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\n" ); document.write( "\n" ); document.write( "\"%28h%2B.1h%29%2B%28c-.1c%29=820\"
\n" ); document.write( "\"1.1h%2B.9c=820\"\r
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\n" ); document.write( "\n" ); document.write( "But we know that \"h=800-c\", so:
\n" ); document.write( "\"1.1%28800-c%29%2B.9c=820\"\r
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\n" ); document.write( "\n" ); document.write( "\"880-1.1c%2B9c=820\"
\n" ); document.write( "\"-.2c=-60\"
\n" ); document.write( "\"c=300\"\r
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\n" ); document.write( "\n" ); document.write( "So, the cow cost 300 and the horse cost 500. The cow sold for 300-30=270, and the horse sold for 500+50=550. Total revenue: 550+270=820 and 20 is 2.5% profit on 800. Answer checks.
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