document.write( "Question 136230: Thanks for the previous questions answered. Pls, I need your help here, and it is urgent\r
\n" ); document.write( "\n" ); document.write( "An object is thrown vertically upward where its height, in meters, is given by
\n" ); document.write( "s(t) = -5t2 + 25t and t is the time, in seconds. Answer the question below.
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\n" ); document.write( "What is the velocity of the object at 1 second after it has been released?
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\n" ); document.write( "Thanks
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Algebra.Com's Answer #99781 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Given:
\n" ); document.write( "\"s%28t%29+=+-5t%5E2%2B25t\" as the function of the height of an object propelled vertically upwards, find the velocity of the object after 1 second.
\n" ); document.write( "Velocity is rate of change of distance (height in this case) with respect to time, t.
\n" ); document.write( "To find the rate of change of the function, you would find the first derivative of s(t).
\n" ); document.write( "\"d%28s%28t%29%29%2Fdt+=+-10t%2B25\" Now substitute t = 1 second.
\n" ); document.write( "\"d%28s%281%29%29%2Fdt+=+-10%281%29%2B25\" = \"15\"
\n" ); document.write( "The velocity at 1 second is 15 m/s.
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