document.write( "Question 136221: SOLVE THE SYSTEM USING THE GAUSS-JORDAN METHOD
\n" );
document.write( "PROBLEM: x-2y= -1
\n" );
document.write( " 2x+y= -7
\n" );
document.write( "PLEASE HELP SOLVE.. I UNDERSTAND THE FORMULA COMPLETLY AND HOW IT SHOULD COME OUT TO LOOK LIKE [ 1 0.. AND BENEATH THAT 0 1..] YET JUST THE PROCESS OF SOLVING IT LOSES ME.. I DO UNDERSTAND HOW TO SET IT UP THOUGH
\n" );
document.write( "[ 1 -2..-1]
\n" );
document.write( "[2 1..-7] THANK YOU FOR YOUR TIME... lj23kfuller@yahoo.com \n" );
document.write( "
Algebra.Com's Answer #99777 by dolly(163)![]() ![]() ![]() You can put this solution on YOUR website! I'll help you\r \n" ); document.write( "\n" ); document.write( "You got the matrix [1 2 -1] \n" ); document.write( " [2 1 -7]\r \n" ); document.write( "\n" ); document.write( "Now we perform row operations basically to make the elements below and above the principal diagonal as 0\r \n" ); document.write( "\n" ); document.write( "Consider R2 - 2 R1 \n" ); document.write( "So the matrix becomes [1 2 -1] \n" ); document.write( " [0 -3 -5]\r \n" ); document.write( "\n" ); document.write( "Now the element below the diagonal became 0\r \n" ); document.write( "\n" ); document.write( "To get the elemnts along the diagonal as 1, \n" ); document.write( "we divide the R2 by -3\r \n" ); document.write( "\n" ); document.write( "==> [1 2 -1] \n" ); document.write( " [0 1 -5/-3]\r \n" ); document.write( "\n" ); document.write( "= [1 2 -1] \n" ); document.write( " [0 1 5/3]\r \n" ); document.write( "\n" ); document.write( "Now to make the element above the diagonal 0, perform\r \n" ); document.write( "\n" ); document.write( "R1 - 2 R2\r \n" ); document.write( "\n" ); document.write( "==> [1 0 -1-10/3] \n" ); document.write( " [0 1 5/3]\r \n" ); document.write( "\n" ); document.write( "==> [1 0 -13/3] \n" ); document.write( " [0 1 5/3]\r \n" ); document.write( "\n" ); document.write( "This represents the original equation\r \n" ); document.write( "\n" ); document.write( "Thus we get x = -13/3 and y = 5/3\r \n" ); document.write( "\n" ); document.write( "These satisfy the given equation.\r \n" ); document.write( "\n" ); document.write( "Hope it is clear\r \n" ); document.write( "\n" ); document.write( "Good luck!!!\r \n" ); document.write( "\n" ); document.write( "Dolly \n" ); document.write( " |