document.write( "Question 20724: I REALLY REALLY NEED HELP A.S.A.P. What is the value of N in the equation: log $\"8\"$ (n-3) + log $\"8\"$ (n+4) = 1. I REALLY REALLY appreciate the help because I really need it. Sorry for the short notice. \n" ); document.write( "

Algebra.Com's Answer #9977 by venugopalramana(3286) $\"\"$ $\"About$

You can put this solution on YOUR website!
i think you mean logs to base 8 ...assuming that and using the formula
\n" ); document.write( "log x to base y = log x /log y...where all logs are taken to any common base.
\n" ); document.write( "so we have
\n" ); document.write( "log(n-3)/log 8 + log(n+4)/log 8 =1....multipling through out with log 8,we get
\n" ); document.write( "log (n-3)+log (n+4)=log 8
\n" ); document.write( "log(n-3)(n+4)=log 8
\n" ); document.write( "hence (n-3)(n+4)=8
\n" ); document.write( "n^2-3n+4n-12-8=0
\n" ); document.write( "n^2+n-20=0
\n" ); document.write( "n^2+5n-4n-20=0
\n" ); document.write( "n(n+5)-4(n+5)=0
\n" ); document.write( "(n+5)(n-4)=0
\n" ); document.write( "hence n=-5 or n=4 \n" ); document.write( "

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