document.write( "Question 136165: 1. Arsenic-74 is used to locate brain tumors. It has a half-life of 17.5 days. Write an exponential decay function for a 90-mg sample. Use the function to find the amount remaining after 6 days?
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Algebra.Com's Answer #99750 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
The formula for a half-life function is \r
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\n" ); document.write( "\n" ); document.write( "\"A%5Br%5D=A%5B0%5D%281%2F2%29%5E%28t%2FH%29\" where \"A%5Br%5D\" is the amount remaining, \"A%5B0%5D\" is the original amount of the substance, and H is the half-life\r
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\n" ); document.write( "\n" ); document.write( "So in our case A=90 and H=17.5\r
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\n" ); document.write( "\n" ); document.write( "\"A%5Br%5D=90%281%2F2%29%5E%28t%2F17.5%29\" Plug in \"A%5B0%5D=90\" and H=17.5\r
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\n" ); document.write( "\n" ); document.write( "\"A%5Br%5D=90%281%2F2%29%5E%286%2F17.5%29\" Since we want to know how much is remaining after 6 days, simply plug in \"t=6\" \r
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\n" ); document.write( "\n" ); document.write( "\"A%5Br%5D=90%281%2F2%29%5E%280.34286%29\" Divide\r
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\n" ); document.write( "\n" ); document.write( "\"A%5Br%5D=90%280.78847%29\" Raise \"1%2F2\" to the 0.34286th power to get 0.78847\r
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\n" ); document.write( "\n" ); document.write( "\"A%5Br%5D=70.9623\" Multiply \r
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\n" ); document.write( "\n" ); document.write( "So in 6 days, there will be about 70.9623 mg of arsenic left over
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