document.write( "Question 136104: solve for S: s(2s-t)=t^2 \n" ); document.write( "
Algebra.Com's Answer #99743 by JSmall(7)\"\" \"About 
You can put this solution on YOUR website!
solve for S: s(2s-t)=t^2\r
\n" ); document.write( "\n" ); document.write( "This solution will be:
\n" ); document.write( "1) Simplify the left side
\n" ); document.write( "2) Get one side of the equation equal to zero.
\n" ); document.write( "3) Factor the other side
\n" ); document.write( "4) Set each factor to zero and solve.\r
\n" ); document.write( "\n" ); document.write( "1) Simplify
\n" ); document.write( " s(2s-t) = t^2
\n" ); document.write( "using the Distributive Proporty
\n" ); document.write( " 2s^2 - st = t^2
\n" ); document.write( "2) Get one side equal to zero by subtracting t^2 from each side:
\n" ); document.write( " 2s^2 - st - t^2 = t^2 - t^2
\n" ); document.write( "which simplifies to
\n" ); document.write( " 2s^2 - st - t^2 = 0
\n" ); document.write( "3) Factor the left side. (Unfortunately there is not enough time and space for me to explain all the details of factoring. I hope that when you see how it factors you will understand.)
\n" ); document.write( " (2s + t) (s - t) = 0
\n" ); document.write( "4) Set each factor to zero. (The only way for a product (multiplication) to result in zero is if one of the factors is zero.) So
\n" ); document.write( " 2s + t = 0
\n" ); document.write( "or
\n" ); document.write( " s - t = 0
\n" ); document.write( "5) Solve each equation
\n" ); document.write( " 2s + t = 0
\n" ); document.write( "Subtract t from each side
\n" ); document.write( " 2s = -t
\n" ); document.write( "Divide each side by two
\n" ); document.write( " s = -t/2\r
\n" ); document.write( "\n" ); document.write( "For the equation s - t = 0 add t to both sides resulting in:
\n" ); document.write( " s = t\r
\n" ); document.write( "\n" ); document.write( "So the solution is
\n" ); document.write( " s = -t/2 or s = t\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );