document.write( "Question 136113: please i need urgent help here. pleaseeeeeeeeeeee
\n" ); document.write( "The height of an object propelled upward from a height of 128 feet at an initial velocity of 112 feet per second is given by the equation h = -16t2 + 112t + 128. After how many seconds does the object hit the ground?
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Algebra.Com's Answer #99724 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
Given: \"h+=+-16t%5E2+%2B+112t+%2B+128\"\r
\n" ); document.write( "\n" ); document.write( "When does it hit the ground? Means, when does h = 0\r
\n" ); document.write( "\n" ); document.write( "\"0+=+-16t%5E2+%2B+112t+%2B+128\"
\n" ); document.write( "\"0+=+-t%5E2+%2B+7t+%2B+8\"
\n" ); document.write( "\"+0+=+t%5E2+-7t+-8\"
\n" ); document.write( "\"+0+=+%28t-8%29%28t%2B1%29\"
\n" ); document.write( "t = 8, -1\r
\n" ); document.write( "\n" ); document.write( "Since t cann hit the ground a second before you throw it, the only reasonable answer is 8 seconds.\r
\n" ); document.write( "\n" ); document.write( "Check your answer by using 8 for t and finding h
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