document.write( "Question 136125: Given P(A),find P(not A).\r
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document.write( "P(A)=98%\r
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Algebra.Com's Answer #99719 by nycsharkman(136) ![]() You can put this solution on YOUR website! Given P(A),find P(not A).\r \n" ); document.write( "\n" ); document.write( "P(A)=98%\r \n" ); document.write( "\n" ); document.write( "First change 98% to a decimal number.\r \n" ); document.write( "\n" ); document.write( "98% becomes 0.98\r \n" ); document.write( "\n" ); document.write( "Now, we apply this rule that P(not A) = 1 - P(A).\r \n" ); document.write( "\n" ); document.write( "Then, 1 - 0.98 = 0.02\r \n" ); document.write( "\n" ); document.write( "So, P(not A) = 0.02 \n" ); document.write( " |