document.write( "Question 136125: Given P(A),find P(not A).\r
\n" ); document.write( "\n" ); document.write( "P(A)=98%\r
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Algebra.Com's Answer #99719 by nycsharkman(136)\"\" \"About 
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Given P(A),find P(not A).\r
\n" ); document.write( "\n" ); document.write( "P(A)=98%\r
\n" ); document.write( "\n" ); document.write( "First change 98% to a decimal number.\r
\n" ); document.write( "\n" ); document.write( "98% becomes 0.98\r
\n" ); document.write( "\n" ); document.write( "Now, we apply this rule that P(not A) = 1 - P(A).\r
\n" ); document.write( "\n" ); document.write( "Then, 1 - 0.98 = 0.02\r
\n" ); document.write( "\n" ); document.write( "So, P(not A) = 0.02
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