document.write( "Question 136159: please, help mw with this\r
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document.write( " A ball is thrown upward at a velocity of 12 feet per second from a height that is 40 feet above the ground. The height A (in feet) of the ball at time t (in seconds), after it is thrown, can be found by the formula h = -12t2 + 14t + 40
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document.write( "Find the time, in seconds, when the ball is again 40 feet above the ground.
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document.write( " Thanks \n" );
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Algebra.Com's Answer #99711 by vleith(2983)![]() ![]() ![]() You can put this solution on YOUR website! Given: \n" ); document.write( "You are asked to find the time(s) when the ball is 40 feet above the ground.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "the value is 0, if either or both terms on the right are 0.\r \n" ); document.write( "\n" ); document.write( "So, 0 = -2t --> t = 0 \n" ); document.write( "0 = (6t-7) --> t = 7/6 \r \n" ); document.write( "\n" ); document.write( "The ball is at 40 feet when you throw it, and again 7/6 seconds later\r \n" ); document.write( "\n" ); document.write( "Check your answer\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |