document.write( "Question 136159: please, help mw with this\r
\n" ); document.write( "\n" ); document.write( " A ball is thrown upward at a velocity of 12 feet per second from a height that is 40 feet above the ground. The height A (in feet) of the ball at time t (in seconds), after it is thrown, can be found by the formula h = -12t2 + 14t + 40
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\n" ); document.write( "\n" ); document.write( "Find the time, in seconds, when the ball is again 40 feet above the ground.
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Algebra.Com's Answer #99711 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
Given: \"h+=+-12t2+%2B+14t+%2B+40++\"
\n" ); document.write( "You are asked to find the time(s) when the ball is 40 feet above the ground.\r
\n" ); document.write( "\n" ); document.write( "\"h+=+-12t2+%2B+14t+%2B+40+\"
\n" ); document.write( "\"40=+-12t2+%2B+14t+%2B+40++\"
\n" ); document.write( "\"+0+=+-12t%5E2+%2B+14t\"
\n" ); document.write( "\"0+=+-2t%286t+-+7%29+\"
\n" ); document.write( "the value is 0, if either or both terms on the right are 0.\r
\n" ); document.write( "\n" ); document.write( "So, 0 = -2t --> t = 0
\n" ); document.write( "0 = (6t-7) --> t = 7/6 \r
\n" ); document.write( "\n" ); document.write( "The ball is at 40 feet when you throw it, and again 7/6 seconds later\r
\n" ); document.write( "\n" ); document.write( "Check your answer\r
\n" ); document.write( "\n" ); document.write( "\"h+=+-12%287%2F6%29%5E2+%2B+14%287%2F6%29+%2B+40+\"
\n" ); document.write( "\"h+=+-16.333+%2B+16.333+%2B+40+\"
\n" ); document.write( "\"h+=+40+\" check
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