document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=136143>Question 136143</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Need help \r<BR>\n" );
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document.write( "Suppose that the heights of adult women in the United States are normally distributed with a mean of 63.5 inches and a standard deviation of 2.4 inches. Jennifer is taller than 90% of the population of U.S. women. How tall (in inches) is Jennifer? Carry your intermediate computations to at least four decimal places. <BR>\n" );
document.write( "Round your answer to at least one decimal place. <BR>\n" );
document.write( "Inches = \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99707 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99707\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We need to find the SD that yields 90% below it. There are tables of SD that give area between +-SD. Let's use that type of table.\r<BR>\n" );
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document.write( "In order to find the SD that gives 90% below, we need to allow for the fact that we are going to include the entire lower half of the normal curve. If we want the upper limit to include 90%, then we will have 40% above the mean. \r<BR>\n" );
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document.write( "We need to find the SD value from our table that yields 2*40% = 80% between +-SD. In my table, that is a value of 1.2816.  \r<BR>\n" );
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document.write( "You can get this from your TI-83 like tis -->http://people.hsc.edu/faculty-staff/robbk/Math121/TI-83/InvStdNormal.html\r<BR>\n" );
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document.write( "So Jen is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=63.5+%2B+2.4%2A1.2816 ALIGN=MIDDLE  ALT=\"63.5+%2B+2.4%2A1.2816\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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