document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=136120>Question 136120</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 6 meters more than 3 times it width. If the perimeter of the rectangle is 84 meters find its dimensions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99706 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=3W+6 IS THE LENGTH<BR>\n" );
document.write( "W=WIDTH<BR>\n" );
document.write( "2L+2W=84<BR>\n" );
document.write( "2(3W+6)+2W=84<BR>\n" );
document.write( "6W+12+2W=84<BR>\n" );
document.write( "8W+12=84<BR>\n" );
document.write( "8W=84-12<BR>\n" );
document.write( "8W=72<BR>\n" );
document.write( "W=72/8<BR>\n" );
document.write( "W=9 ANSWER FOR THE WIDTH<BR>\n" );
document.write( "L=3*9+6<BR>\n" );
document.write( "L=27+6<BR>\n" );
document.write( "L=33 ANSWER<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "2*9+2*33=84<BR>\n" );
document.write( "18+66=84<BR>\n" );
document.write( "84=84<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );