document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=136151>Question 136151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please, am in dire need of the answer to this question. it is urgent.\r<BR>\n" );
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document.write( " A rectangular yard is to be constructed along the side of a house using a fence on three sides.   The house wall will serve as the fourth side. Find the dimensions that produce the maximum area if 40 meters of fence is available.\r<BR>\n" );
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document.write( "Thanks.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99697 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99697\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE MAXIMUM AREA FOR A 3 SIDED FENCE HAS A RATIO OF 1:2:1.<BR>\n" );
document.write( "THE SUM OF THESE RATIOS=4.<BR>\n" );
document.write( "THUS WE DIVIDE THE LENGTH OF THE FENCING 40/4=10.<BR>\n" );
document.write( "THUS THE SIDES ARE 10:20:10.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "10*20=200 YD^2 ANSWER.<BR>\n" );
document.write( "9*22=198 YD^2 <BR>\n" );
document.write( "11*18=198 YD^2.     </SPAN>\n" );
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