document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=136133>Question 136133</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given P(A),find P (not A)\r<BR>\n" );
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document.write( "Events A and B are dependent.P(A) = 5/12 and P(B given A) = 6/11. Find (A and B)\r<BR>\n" );
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document.write( "Thank You for the straightfoward and correct answers you all send me. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99690 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99690\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the probability of A occurring is x%, then the probability of \"not A\" is 100-x%. \r<BR>\n" );
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document.write( "If the probability of A is 'x out of y', the probability of 'not A', is '(y-x) out of y. \r<BR>\n" );
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document.write( "The net result is the sum of the two probabilities must be one (or 100%)\r<BR>\n" );
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document.write( "Bayes Theorem states:<BR>\n" );
document.write( "P(A and B) = P(B)* P(A|B) = P(A)*P(B|A)\r<BR>\n" );
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document.write( "You are given P(A) and P(B|A) - you can do the math :-D </SPAN>\n" );
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