document.write( "Question 136114: Linear functions
\n" ); document.write( "y=3/4x + 2, find x if y=2/3
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Algebra.Com's Answer #99681 by ijeoma(3)\"\" \"About 
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if y=2/3
\n" ); document.write( "plug in the value of y in the y=3/4x and solve for x
\n" ); document.write( "therefore; 2/3=3/4x
\n" ); document.write( "multiply both sides by 4/3
\n" ); document.write( "2/3 x 4/3=3/4(4/3)x
\n" ); document.write( "8/9=x
\n" ); document.write( " therefore x is 8/9\r
\n" ); document.write( "\n" ); document.write( "Proof
\n" ); document.write( "substitute the value of x in y=3/4x and u will have the original value of y
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