document.write( "Question 136095: Dr. Kingsley took 60 ounces of a 20% gold alloy and mixed it with a 30% gold alloy to get a 24% gold alloy. How many ounces of the 30% gold alloy did he use? \n" ); document.write( "
Algebra.Com's Answer #99675 by stanbon(75887)\"\" \"About 
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Dr. Kingsley took 60 ounces of a 20% gold alloy and mixed it with a 30% gold alloy to get a 24% gold alloy. How many ounces of the 30% gold alloy did he use?
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\n" ); document.write( "20% DATA:
\n" ); document.write( "Amount = 60 oz ; amt. of gold = 0.20*60 = 12 oz
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\n" ); document.write( "30% DATA:
\n" ); document.write( "Amount = x oz ; amt. of gold = 0.30x oz
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\n" ); document.write( "Alloy DATA:
\n" ); document.write( "Amount = x+60 oz ; amt of gold = 0.24(x+60) oz
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\n" ); document.write( "EQUATION:
\n" ); document.write( "gold + gold = gold
\n" ); document.write( "12 + 0.30x = 0.24x + 14.4
\n" ); document.write( "0.06x = 2.4
\n" ); document.write( "x = 40 oz (Amount of 30% in the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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