document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=136061>Question 136061</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My question is regarding Sessa's reward.  What is the equation to determine the total number of grains of rice after 64 days? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99664 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99664\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> My question is regarding Sessa's reward.  What is the equation to determine the total number of grains of rice after 64 days?<BR>\n" );
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document.write( "It's probably 1+2+2^2+2^3+2^4+2^5+ ...+ 2^63<BR>\n" );
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document.write( "S(n) = a[r^n-1]/[r-1] where r = 2<BR>\n" );
document.write( "S(64)= 1[2^64 -1]/[2-1] = 2^64 -1 -1.844674407 x 10^19 grains<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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