document.write( "Question 20730: Can anyone help solve this?\r
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document.write( "1 - logx = log(3x-1)\r
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document.write( "I tried:
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document.write( "1 - logx = log 3x - log 1
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document.write( "1 = logx + log 3x - log 1
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document.write( "1 = log4x - log 1\r
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document.write( "I also tried:
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document.write( "1 - logx = log(3x-1)
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document.write( "divide both sides by log
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document.write( "1-x = (3x-1)
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document.write( "2 - x = 3x
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document.write( "2 = 4x
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document.write( "1/2 = x\r
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document.write( "Or:
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document.write( "1 - logx = log(3x-1)
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document.write( "1 - 10 = log3x - log
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document.write( "-9 = 3logx - log
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document.write( "-9 = 3(10) - log
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document.write( "-9 = 30 - log
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document.write( "-39 = -log\r
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document.write( "The teacher's answer is 2
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document.write( "Can anyone help?\r
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document.write( "Thanks,
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document.write( "Sandy \n" );
document.write( "
Algebra.Com's Answer #9966 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "If \n" ); document.write( "If \n" ); document.write( "\n" ); document.write( "The roots are: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "1) x = 2 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2) \n" ); document.write( "1-log((-5/3)) = 0.77815..., -1.36437... \n" ); document.write( "log(3(-5/3)-1) = 0.77815..., 1.36437... \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer is x = 2 \n" ); document.write( " \n" ); document.write( " |