document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135988>Question 135988</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help with this question.  Determine the area of the triangle to the nearest tenth. Use A=bh/2.   It is a right triangle 30-60-90  and the base measure is 6squareroot3.  The height is not given.  Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99646 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99646\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The trouble is, you didn't specify which of the triangle legs you are calling the base.\r<BR>\n" );
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document.write( "Assumption:  The longer leg is the base:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28600%2C400%2C-1%2C12%2C-1%2C8%2C%0D%0Atriangle%280%2C0%2C0%2C6%2C6sqrt%283%29%2C0%29%2C%0D%0Alocate%283sqrt%283%29-.2%2C-.5%2Cbase%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "A 30-60-90 triangle has sides in the following proportion:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2 ALIGN=MIDDLE  ALT=\"1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >:<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283%29%2F2 ALIGN=MIDDLE  ALT=\"sqrt%283%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >:<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1 ALIGN=MIDDLE  ALT=\"1\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "That means the shorter leg is half the length of the hypotenuse and the longer leg is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283%29%2F2 ALIGN=MIDDLE  ALT=\"sqrt%283%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > times the hypotenuse.  And the long leg is then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > times the short leg.\r<BR>\n" );
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document.write( "Here your long leg is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6sqrt%283%29 ALIGN=MIDDLE  ALT=\"6sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so the short leg, and the height of the triangle must be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6sqrt%283%29%2Fsqrt%283%29=6 ALIGN=MIDDLE  ALT=\"6sqrt%283%29%2Fsqrt%283%29=6\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Therefore your area is given by:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=%286%2A6sqrt%283%29%29%2F2=18sqrt%283%29 ALIGN=MIDDLE  ALT=\"A=%286%2A6sqrt%283%29%29%2F2=18sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Assumption:  The shorter leg is the base:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28400%2C600%2C-1%2C12%2C-1%2C20%2C%0D%0Atriangle%280%2C0%2C0%2C18%2C6sqrt%283%29%2C0%29%2C%0D%0Alocate%283-.2%2C-.5%2Cbase%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Here your short leg is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6sqrt%283%29 ALIGN=MIDDLE  ALT=\"6sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so the long leg, and the height of the triangle must be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6sqrt%283%29%2Asqrt%283%29=6%2A3=18 ALIGN=MIDDLE  ALT=\"6sqrt%283%29%2Asqrt%283%29=6%2A3=18\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Therefore your area is given by:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=%2818%2A6sqrt%283%29%29%2F2=54sqrt%283%29 ALIGN=MIDDLE  ALT=\"A=%2818%2A6sqrt%283%29%29%2F2=54sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Makes a difference by a factor of 3. </SPAN>\n" );
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